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← JEE Main 2015 · 4 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 65 of 90

JEE Main 2015 · 4 Apr · Shift 1, Mathematics question 65

The set of all values of λ for which the system of linear equations :
2x1−2x2+x3=λx12x_1-2x_2+x_3=\lambda x_1
2x1−3x2+2x3=λx22x_1-3x_2+2x_3=\lambda x_2
−x1+2x2=λx3-x_1+2x_2=\lambda x_3
has a non-trivial solution,

Choose one option
Answer and worked solution

Official answer: C

Non-trivial solutions need det⁡(A−λI)=0\det(A-\lambda I)=0 for A=[2−212−32−120]A=\begin{bmatrix}2&-2&1\\2&-3&2\\-1&2&0\end{bmatrix}:
λ3+λ2−5λ+3=(λ−1)2(λ+3)=0.\lambda^3+\lambda^2-5\lambda+3=(\lambda-1)^2(\lambda+3)=0.
So λ ∈ {1, −3}: two elements.