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← JEE Main 2014 · 12 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 80 of 90

JEE Main 2014 · 12 Apr · Shift 1, Mathematics question 80

For the two circles x2+y2=16x^2+y^2=16 and x2+y2−2y=0x^2+y^2-2y=0, there is/are :

Choose one option
Answer and worked solution

Official answer: D

The second circle has centre (0,1)(0,1), radius 1. Its distance from the origin is 1, less than 4−1=34-1=3, so it lies inside the first circle. There is no common tangent.