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← JEE Main 2014 · 12 Apr · Shift 1
MathematicsSingle correct+4 / -1Question 79 of 90

JEE Main 2014 · 12 Apr · Shift 1, Mathematics question 79

If the three distinct lines x+2ay+a=0x+2ay+a=0, x+3by+b=0x+3by+b=0 and x+4ay+a=0x+4ay+a=0 are concurrent, then the point (a, b) lies on a :

Choose one option
Answer and worked solution

Official answer: C

∣12aa13bb14aa∣=0.\begin{vmatrix}1&2a&a\\1&3b&b\\1&4a&a\end{vmatrix}=0.
Subtracting R1R_1 from R2R_2 and R3R_3 and expanding gives −2a(b−a)=0-2a(b-a)=0. With a≠0a\ne0 (else lines 1 and 3 coincide), a=ba=b: the point lies on the straight line y=xy=x.