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JEE Main 2014 · 11 Apr · Shift 1, Physics question 18

In the circuit shown, current (in A) through the 50 V and 30 V batteries are, respectively :

A 50 V battery on the left and a 30 V battery on the right; between them a 5 Ω resistor on the top wire and a 5 Ω resistor on the bottom wire, with a 20 Ω resistor and a 10 Ω resistor connected across from top to bottom.
Choose one option
Answer and worked solution

Official answer: C

  • The 50 V battery is directly across the 20 Ω resistor: 2.5 A through it.
  • The 30 V battery is directly across the 10 Ω resistor: 3 A through it.
  • Round the outer loop (both 5 Ω resistors), the current is 50−3010=2\dfrac{50-30}{10}=2 A.

So the 50 V battery carries 2.5+2=4.52.5+2=4.5 A, and the 30 V battery 3−2=13-2=1 A.

Topics:Kirchhoff's laws
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