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← JEE Main 2014 · 11 Apr · Shift 1
ChemistrySingle correct+4 / -1Question 34 of 90

JEE Main 2014 · 11 Apr · Shift 1, Chemistry question 34

Assuming that the degree of hydrolysis is small, the pH of 0.1 M solution of sodium acetate (Ka=1.0×10−5K_a=1.0\times10^{-5}) will be :

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Answer and worked solution

Official answer: D

For the salt of a weak acid and a strong base:
pH=7+12(pKa+log⁡C)=7+12(5−1)=9.\text{pH}=7+\tfrac12(pK_a+\log C)=7+\tfrac12(5-1)=9.