JEE Main 2014 · 9 Apr · Shift 1 · Physics Q28

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PhysicsSingle correct+4 / -1Question 28 of 90

Identify the gate and match A, B, Y in bracket to check.

Inputs A and B go to a NAND gate whose output (A·B with a bar) feeds both inputs of a second NAND gate, giving Y.

AND (A = 1, B = 1, Y = 1)

OR (A = 1, B = 1, Y = 0)

NOT (A = 1, B = 1, Y = 1)

XOR (A = 0, B = 0, Y = 0)

Answer and worked solution

Official answer: A

The first gate is NAND: $\overline{A\cdot B}$ . The second NAND has both inputs tied, so it acts as NOT. Then $Y=\overline{\overline{AB}}=AB$ : an AND gate, and $A=B=1$ gives $Y=1$ .

Topics:Logic gates

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JEE Main 2014 · 9 Apr · Shift 1, Physics question 28