JEE Main 2014 · 6 Apr · Shift 1 · Chemistry Q51

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ChemistrySingle correct+4 / -1Question 51 of 90

In $S_N2$ reactions, the correct order of reactivity for the following compounds : $\ce{CH3Cl}$ , $\ce{CH3CH2Cl}$ , $\ce{(CH3)2CHCl}$ and $\ce{(CH3)3CCl}$ is :

\ce{CH3Cl > (CH3)2CHCl > CH3CH2Cl > (CH3)3CCl}

\ce{CH3Cl > CH3CH2Cl > (CH3)2CHCl > (CH3)3CCl}

\ce{CH3CH2Cl > CH3Cl > (CH3)2CHCl > (CH3)3CCl}

\ce{(CH3)2CHCl > CH3CH2Cl > CH3Cl > (CH3)3CCl}

Answer and worked solution

Official answer: B

$S_N2$ rates fall with steric hindrance at the carbon attacked: methyl > primary > secondary > tertiary:
$\ce{CH3Cl > CH3CH2Cl > (CH3)2CHCl > (CH3)3CCl}.$

Topics:SN1 and SN2

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JEE Main 2014 · 6 Apr · Shift 1, Chemistry question 51