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← JEE Advanced 2026 · Paper 2
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JEE Advanced 2026 · Paper 2, Physics question 14

In a new system of units, the units of mass, length, time and current are 55 kg, 55 m, 55 s and 55 A, respectively. If μ0\mu_0 and ϵ0\epsilon_0 are the permeability and permittivity of free space, respectively, then in this new system of units, the magnitude of one SI unit of μ0/ϵ0\sqrt{\mu_0/\epsilon_0}, is:

Answer and worked solution

Official answer: 25

μ0/ϵ0\sqrt{\mu_0/\epsilon_0} has the dimensions of resistance:
[Ω]=kg m2 s−3 A−2.[\Omega]=\text{kg m}^2\,\text{s}^{-3}\,\text{A}^{-2}.
The new unit of resistance is
5⋅5253⋅52 Ω=125 Ω.\frac{5\cdot5^2}{5^3\cdot5^2}\ \Omega=\frac1{25}\ \Omega.
So one SI unit (1 Ω) equals 25 new units.