JEE Advanced 2026 · Paper 1 · Chemistry Q14

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ChemistryList match+4 / -1Question 46 of 48

Consider the following species:

$\ce{SOCl2}$ , $\ce{XeOF4}$ , $\ce{ClF3}$ , $\ce{ClF5}$ , $\ce{XeF5+}$ , $\ce{SO3^2-}$ , $\ce{XeF3+}$ , $\ce{SF4}$

List-I contains different molecular shapes and List-II contains total number of species with the same molecular shapes from the given species. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

List-I

P
See-saw
Q
T-Shaped
R
Trigonal Planar
S
Square Pyramidal

List-II

1
one
2
two
3
three
4
four
5
zero

P → 1; Q → 2; R → 5; S → 3

P → 5; Q → 4; R → 2; S → 3

P → 3; Q → 2; R → 1; S → 4

P → 1; Q → 3; R → 5; S → 4

Answer and worked solution

Official answer: A

Shapes by VSEPR (bonded pairs + lone pairs on the central atom):

Species	Pairs (bp + lp)	Shape
$\ce{SOCl2}$	3 + 1	trigonal pyramidal
$\ce{XeOF4}$	5 + 1	square pyramidal
$\ce{ClF3}$	3 + 2	T-shaped
$\ce{ClF5}$	5 + 1	square pyramidal
$\ce{XeF5+}$	5 + 1	square pyramidal
$\ce{SO3^2-}$	3 + 1	trigonal pyramidal
$\ce{XeF3+}$	3 + 2	T-shaped
$\ce{SF4}$	4 + 1	see-saw

Counts:

see-saw: one → 1;
T-shaped: two → 2;
trigonal planar: zero → 5;
square pyramidal: three → 3.

P→1, Q→2, R→5, S→3.

Topics:VSEPR theory

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JEE Advanced 2026 · Paper 1, Chemistry question 14