JEE Advanced 2026 · Paper 1 · Chemistry Q7

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ChemistryMultiple correct+4 / -1Question 39 of 48

Reaction of $\ce{PtF6}$ with oxygen $(\ce{O2})$ gas results in the formation of an ionic compound, $\mathbf X^+\mathbf Y^-$ . Correct statement(s) is(are)

The bond order of

\mathbf X^+

is 1.5.

Valence

d

-orbitals of the metal ion in

\mathbf X^+\mathbf Y^-

has 5 electrons.

\ce{PtF6}

acts as an oxidant in this reaction.

\ce{PtF6}

acts as a fluorinating agent in this reaction.

Answer and worked solution

Official answer: B, C

$\ce{O2 + PtF6 -> O2+[PtF6]-}$ (dioxygenyl hexafluoroplatinate), so X $^+=\ce{O2+}$ and Y $^-=\ce{PtF6-}$ .

(A) $\ce{O2+}$ has 15 electrons, bond order $\frac{10-5}2=2.5$ . False.

(B) In $\ce{PtF6-}$ platinum is +5: $\ce{Pt}$ is $5d^96s^1$ , so $\ce{Pt^5+}$ is $5d^5$ . True.

(C) $\ce{PtF6}$ takes an electron from $\ce{O2}$ , so it is the oxidant. True.

(D) No fluorine is transferred to oxygen. False.

Topics:Group 18 Molecular orbital theory Oxidation number

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