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← JEE Advanced 2026 · Paper 1
ChemistryMultiple correct+4 / -1Question 38 of 48

JEE Advanced 2026 · Paper 1, Chemistry question 6

Correct statement(s) about the compounds X, Y and Z is(are)

MnOX2+Conc ⋅ HCl→MnClX2\ce{MnO2 + Conc. HCl -> MnCl2} + X (greenish yellow gas) + HX2O\ce{H2O}

NHX3\ce{NH3} + X (excess) ⟶\longrightarrow Y + HCl

X + FX2\ce{F2} (excess) →573 K\xrightarrow{573\ \mathrm K} Z

Choose one or more options
Answer and worked solution

Official answer: A, C

The compounds.

  • MnOX2+4 HCl→MnClX2+ClX2+2 HX2O\ce{MnO2 + 4HCl -> MnCl2 + Cl2 + 2H2O}, so X =ClX2=\ce{Cl2}.
  • NHX3+3 ClX2 (excess)→NClX3+3 HCl\ce{NH3 + 3Cl2 (excess) -> NCl3 + 3HCl}, so Y =NClX3=\ce{NCl3}.
  • ClX2+3 FX2 (excess)→573 K2 ClFX3\ce{Cl2 + 3F2 (excess) ->[573 K] 2ClF3}, so Z =ClFX3=\ce{ClF3}.

(A) Chlorine is used to disinfect drinking water. True.

(B) NClX3\ce{NCl3} has a lone pair on N: trigonal pyramidal. False.

(C) ClFX3\ce{ClF3} fluorinates uranium to UFX6\ce{UF6}, the volatile compound used to enrich 235^{235}U. True.

(D) The electronegative Cl atoms make NClX3\ce{NCl3} a much weaker base than NHX3\ce{NH3}. False.