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← JEE Advanced 2024 · Paper 1
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JEE Advanced 2024 · Paper 1, Physics question 9

A disc of mass MM and radius RR is free to rotate about its vertical axis as shown in the figure. A battery operated motor of negligible mass is fixed to this disc at a point on its circumference. Another disc of the same mass MM and radius R/2R/2 is fixed to the motor's thin shaft. Initially, both the discs are at rest. The motor is switched on so that the smaller disc rotates at a uniform angular speed ω\omega. If the angular speed at which the large disc rotates is ω/n\omega/n, then the value of nn is _____.

Perspective view of two horizontal discs. A large disc of mass M and radius R (radius arrow drawn from its centre) has a vertical dashed axis through its centre. A smaller disc of mass M and radius R/2 (radius arrow drawn from its centre) sits on top of the large disc's rim, overlapping its edge on the left; the small disc has its own vertical dashed axis through its centre, which passes through a point on the circumference of the large disc. The two dashed axes are parallel and separated by R.
Answer and worked solution

Official answer: 12

The motor's torque is internal and the large disc's axis is fixed, so angular momentum about that axis stays zero.

Let the large disc turn at Ω\Omega and the small disc spin at ω\omega (relative to the ground). The small disc's centre moves on a circle of radius RR with angular speed Ω\Omega:
(12MR2+MR2)Ω+12M(R2)2ω=0  ⟹  32Ω=−18ω.\left(\tfrac12 MR^2 + MR^2\right)\Omega + \tfrac12 M\left(\tfrac R2\right)^2\omega = 0 \implies \tfrac32\Omega = -\tfrac18\omega.

∣Ω∣=ω12|\Omega| = \dfrac{\omega}{12}, so n=12n = 12.