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← JEE Advanced 2024 · Paper 1
PhysicsInteger+4Question 25 of 51

JEE Advanced 2024 · Paper 1, Physics question 8

The specific heat capacity of a substance is temperature dependent and is given by the formula C=kTC = kT, where kk is a constant of suitable dimensions in SI units, and TT is the absolute temperature. If the heat required to raise the temperature of 1 kg1\,\mathrm{kg} of the substance from −73 ∘C-73\,^{\circ}\mathrm{C} to 27 ∘C27\,^{\circ}\mathrm{C} is nknk, the value of nn is _____.

[Given: 0 K=−273 ∘C0\,\mathrm{K} = -273\,^{\circ}\mathrm{C}.]

Answer and worked solution

Official answer: 25000

T1=200 KT_1 = 200\,\mathrm{K} and T2=300 KT_2 = 300\,\mathrm{K}.
Q=∫200300m kT dT=k 3002−20022=25000 k.Q = \int_{200}^{300} m\,kT\,dT = k\,\frac{300^2 - 200^2}{2} = 25000\,k.
So n=25000n = 25000.