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← JEE Advanced 2023 · Paper 2
ChemistryMultiple correct+4 / -2Question 40 of 51

JEE Advanced 2023 · Paper 2, Chemistry question 6

Atoms of metals x, y, and z form face-centred cubic (fcc) unit cell of edge length LxL_x, body-centred cubic (bcc) unit cell of edge length LyL_y, and simple cubic unit cell of edge length LzL_z, respectively.

If rz=32ryr_z = \dfrac{\sqrt3}{2}r_y; ry=83rxr_y = \dfrac{8}{\sqrt3}r_x; Mz=32MyM_z = \dfrac32 M_y and Mz=3MxM_z = 3M_x, then the correct statement(s) is(are)

[Given: MxM_x, MyM_y, and MzM_z are molar masses of metals x, y, and z, respectively. rxr_x, ryr_y, and rzr_z are atomic radii of metals x, y, and z, respectively.]

Choose one or more options
Answer and worked solution

Official answer: A, B, D

Edge lengths in terms of rxr_x.

  • fcc: Lx=22 rxL_x=2\sqrt2\,r_x.
  • bcc: Ly=4ry3L_y=\frac{4r_y}{\sqrt3}. With ry=83rxr_y=\frac{8}{\sqrt3}r_x, Ly=323rx≈10.7 rxL_y=\frac{32}{3}r_x\approx10.7\,r_x.
  • simple cubic: Lz=2rzL_z=2r_z. With rz=32ry=4rxr_z=\frac{\sqrt3}2r_y=4r_x, Lz=8rxL_z=8r_x.

(A) True. Packing efficiencies are 74% (fcc) > 68% (bcc) > 52% (sc).

(B) True. Ly≈10.7 rx>Lz=8 rxL_y\approx10.7\,r_x>L_z=8\,r_x.

(C) False. Lx≈2.83 rx<LyL_x\approx2.83\,r_x<L_y.

(D) True. ρ=ZMNAL3\rho=\dfrac{ZM}{N_AL^3}, and My=23Mz=2MxM_y=\frac23M_z=2M_x:

  • ρx∝4Mx(22)3=0.177 Mx\rho_x\propto\dfrac{4M_x}{(2\sqrt2)^3}=0.177\,M_x;
  • ρy∝2⋅2Mx(32/3)3=0.0033 Mx\rho_y\propto\dfrac{2\cdot2M_x}{(32/3)^3}=0.0033\,M_x.

So x is much denser.