JEE Advanced 2023 · Paper 1 · Physics Q15

PhysicsList match+3 / -1Question 32 of 51

Match the temperature of a black body given in List-I with an appropriate statement in List-II, and choose the correct option.

[Given: Wien's constant as $2.9\times10^{-3}$ m-K and $\dfrac{hc}{e} = 1.24\times10^{-6}$ V-m]

List-I

List-II

1
The radiation at peak wavelength can lead to emission of photoelectrons from a metal of work function 4 eV.
2
The radiation at peak wavelength is visible to human eye.
3
The radiation at peak emission wavelength will result in the widest central maximum of a single slit diffraction.
4
The power emitted per unit area is 1/16 of that emitted by a blackbody at temperature 6000 K.
5
The radiation at peak emission wavelength can be used to image human bones.

P → 3; Q → 5; R → 2; S → 3

P → 3; Q → 2; R → 4; S → 1

P → 3; Q → 4; R → 2; S → 1

P → 1; Q → 2; R → 5; S → 3

Answer and worked solution

Official answer: C

Peak wavelengths from $\lambda_m=\dfrac{2.9\times10^{-3}}{T}$ :

T	$\lambda_m$	Photon energy, $1240/\lambda_m$ (eV, $\lambda_m$ in nm)
2000 K	1450 nm (infrared)	0.86 eV
3000 K	967 nm	1.28 eV
5000 K	580 nm (visible)	2.14 eV
10000 K	290 nm (UV)	4.28 eV

Matching.

No temperature peaks in the X-ray range, so (5) is unused.

P→3, Q→4, R→2, S→1.

JEE Advanced 2023 · Paper 1, Physics question 15