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JEE Advanced 2023 · Paper 1, Physics question 14

List-I shows different radioactive decay processes and List-II provides possible emitted particles. Match each entry in List-I with an appropriate entry from List-II, and choose the correct option.

List-I

  • P
    92238U→91234Pa{}^{238}_{92}U \to {}^{234}_{91}Pa
  • Q
    82214Pb→82210Pb{}^{214}_{82}Pb \to {}^{210}_{82}Pb
  • R
    81210Tl→82206Pb{}^{210}_{81}Tl \to {}^{206}_{82}Pb
  • S
    91228Pa→88224Ra{}^{228}_{91}Pa \to {}^{224}_{88}Ra

List-II

  • 1
    one α\alpha particle and one β+\beta^+ particle
  • 2
    three β−\beta^- particles and one α\alpha particle
  • 3
    two β−\beta^- particles and one α\alpha particle
  • 4
    one α\alpha particle and one β−\beta^- particle
  • 5
    one α\alpha particle and two β+\beta^+ particles
Choose one option
Answer and worked solution

Official answer: A

In every case the mass number drops by 4, so exactly one α\alpha is emitted, lowering ZZ by 2. Beta particles then fix the charge.

Decay ZZ after one α\alpha Final ZZ Betas Match
(P) 92238^{238}_{92}U → 91234^{234}_{91}Pa 90 91 one β−\beta^- 4
(Q) 82214^{214}_{82}Pb → 82210^{210}_{82}Pb 80 82 two β−\beta^- 3
(R) 81210^{210}_{81}Tl → 82206^{206}_{82}Pb 79 82 three β−\beta^- 2
(S) 91228^{228}_{91}Pa → 88224^{224}_{88}Ra 89 88 one β+\beta^+ 1

P→4, Q→3, R→2, S→1.

Topics:Radioactive decay
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