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← JEE Advanced 2022 · Paper 2
MathematicsInteger+3 / -1Question 4 of 54

JEE Advanced 2022 · Paper 2, Mathematics question 4

The product of all positive real values of xx satisfying the equation
x(16(log⁡5x)3−68log⁡5x)=5−16x^{\left(16(\log_5 x)^3 - 68\log_5 x\right)} = 5^{-16}
is _____.

Answer and worked solution

Official answer: 1

Take log⁡5\log_5. Let t=log⁡5xt=\log_5x. Then
(16t3−68t) t=−16  ⟹  4t4−17t2+4=0  ⟹  (4t2−1)(t2−4)=0.(16t^3-68t)\,t=-16\implies4t^4-17t^2+4=0\implies(4t^2-1)(t^2-4)=0.

Roots. t=±12, ±2t=\pm\frac12,\ \pm2, all real, so there are four positive x=5tx=5^t.

Product.
∏x=5∑t=50=1.\prod x=5^{\sum t}=5^0=1.