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ChemistryInteger+3 / -1Question 43 of 54

JEE Advanced 2022 · Paper 2, Chemistry question 7

The number of −CH2−-\mathrm{CH_2}- (methylene) groups in the product formed from the following reaction sequence is ________.

(E)-Oct-4-ene (skeletal zigzag, trans C=C between C4 and C5) treated with 1. O3, Zn/H2O; 2. KMnO4; 3. NaOH, electrolysis; 4. Cr2O3, 770 K, 20 atm.
Answer and worked solution

Official answer: 0

Step by step.

  1. Ozonolysis of oct-4-ene (OX3\ce{O3}, Zn/HX2O\ce{H2O}) gives 2 molecules of butanal.
  2. KMnOX4\ce{KMnO4} oxidises it to butanoic acid.
  3. Kolbe electrolysis of sodium butanoate couples two propyl radicals: 2 CX3HX7COOX−→CX6HX14+2 COX2\ce{2C3H7COO- -> C6H14 + 2CO2}, giving n-hexane.
  4. CrX2OX3\ce{Cr2O3} at 770 K and 20 atm aromatises hexane to benzene.

Benzene has 0 −CHX2−\ce{-CH2-} groups.