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← JEE Advanced 2022 · Paper 2
ChemistryInteger+3 / -1Question 41 of 54

JEE Advanced 2022 · Paper 2, Chemistry question 5

Thermal decomposition of AgNOX3\ce{AgNO3} produces two paramagnetic gases. The total number of electrons present in the antibonding molecular orbitals of the gas that has the higher number of unpaired electrons is ________.

Answer and worked solution

Official answer: 6

Decomposition.
2 AgNOX3→2 Ag+2 NOX2+OX2.\ce{2AgNO3 -> 2Ag + 2NO2 + O2}.
Both gases are paramagnetic: NOX2\ce{NO2} has 1 unpaired electron and OX2\ce{O2} has 2. So the gas meant is OX2\ce{O2}.

MO configuration of OX2\ce{O2} (16 electrons):
σ1s2 σ1s∗2 σ2s2 σ2s∗2 σ2pz2 π2p4 π2p∗2.\sigma_{1s}^2\,\sigma_{1s}^{*2}\,\sigma_{2s}^2\,\sigma_{2s}^{*2}\,\sigma_{2p_z}^2\,\pi_{2p}^4\,\pi_{2p}^{*2}.

Antibonding electrons. 2+2+2=62+2+2=6.