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← JEE Advanced 2022 · Paper 1
PhysicsMultiple correct+4 / -2Question 29 of 54

JEE Advanced 2022 · Paper 1, Physics question 11

An ideal gas of density ρ=0.2 kg m−3\rho = 0.2\ \mathrm{kg\,m^{-3}} enters a chimney of height hh at the rate of α=0.8 kg s−1\alpha = 0.8\ \mathrm{kg\,s^{-1}} from its lower end, and escapes through the upper end as shown in the figure. The cross-sectional area of the lower end is A1=0.1 m2A_1 = 0.1\ \mathrm m^2 and the upper end is A2=0.4 m2A_2 = 0.4\ \mathrm m^2. The pressure and the temperature of the gas at the lower end are 600 Pa and 300 K, respectively, while its temperature at the upper end is 150 K. The chimney is heat insulated so that the gas undergoes adiabatic expansion. Take g=10 m s−2g = 10\ \mathrm{m\,s^{-2}} and the ratio of specific heats of the gas γ=2\gamma = 2. Ignore atmospheric pressure.

Which of the following statement(s) is(are) correct?

A vertical chimney of height h: a narrow tube at the bottom with cross-section A1 widens through a conical section into a wide cylinder with top cross-section A2. Arrows show gas entering upward at the bottom and flowing up through the top.
Choose one or more options
Answer and worked solution

Official answer: B

Adiabatic changes. With γ=2\gamma=2, T∝ργ−1=ρT\propto\rho^{\gamma-1}=\rho.

  • The temperature halves, so ρ2=0.1\rho_2=0.1 kg m⁻³. (D) is false.
  • P∝ρTP\propto\rho T, so P2=600×12×12=150P_2=600\times\frac12\times\frac12=150 Pa. (A) is false.

(B) True. From the mass flow rate:
v1=αρ1A1=0.80.02=40 m s−1,v2=0.80.1×0.4=20 m s−1.v_1=\frac{\alpha}{\rho_1A_1}=\frac{0.8}{0.02}=40\ \text{m s}^{-1},\qquad v_2=\frac{0.8}{0.1\times0.4}=20\ \text{m s}^{-1}.

(C) False. For adiabatic flow, Bernoulli's equation takes the form γγ−1Pρ+v22+gh=\frac{\gamma}{\gamma-1}\frac P\rho+\frac{v^2}2+gh= const:
2(3000)+800=2(1500)+200+10h  ⟹  h=360 m,2(3000)+800=2(1500)+200+10h\implies h=360\ \text{m},
not 590 m.