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← JEE Advanced 2020 · Paper 2
ChemistryInteger+3 / -1Question 19 of 54

JEE Advanced 2020 · Paper 2, Chemistry question 1

The 1st, 2nd, and the 3rd ionization enthalpies, I1I_1, I2I_2, and I3I_3, of four atoms with atomic numbers nn, n+1n+1, n+2n+2, and n+3n+3, where n<10n < 10, are tabulated below. What is the value of nn?

Ionization enthalpies (kJ/mol) of four consecutive elements.
Answer and worked solution

Official answer: 9

Read the table.

  • n+2n+2 has a very low I1I_1 (496) and a huge jump to I2I_2: an alkali metal.
  • n+3n+3 has a low I1I_1 and I2I_2 and a huge jump to I3I_3: an alkaline earth metal.

With n<10n<10, n+2n+2 is Na (11) and n+3n+3 is Mg (12). Then nn is F (I₁ = 1681) and n+1n+1 is Ne (I₁ = 2081), which both fit.

Answer: 9