JEE Advanced 2019 · Paper 2 · Chemistry Q10

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ChemistryNumerical+3Question 28 of 54

Total number of cis N-Mn-Cl bond angles (that is, Mn-N and Mn-Cl bonds in cis positions) present in a molecule of cis- $\ce{[Mn(\mathit{en})2Cl2]}$ complex is ______ ( $en = \ce{NH2CH2CH2NH2}$ )

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Answer and worked solution

Official answer: 6

Arrangement. In octahedral cis- $\ce{[Mn(en)2Cl2]}$ the two Cl ligands are adjacent, and the other four positions are N atoms.

Counting. Each Cl has four cis neighbours: the other Cl and three N. So each Cl makes 3 cis N-Mn-Cl angles, giving $2\times3=6$ .

Answer: 6

Topics:Isomerism in complexes

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JEE Advanced 2019 · Paper 2, Chemistry question 10