JEE Advanced 2019 · Paper 2 · Chemistry Q9

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ChemistryNumerical+3Question 27 of 54

The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. $\ce{HNO3}$ to a compound with the highest oxidation state of sulphur is ______

(Given data: Molar mass of water = 18 g mol⁻¹)

Your answer

Answer and worked solution

Official answer: 288

The reaction. Conc. nitric acid oxidises sulphur to +6, as $\ce{H2SO4}$ :
$\ce{S8 + 48HNO3 -> 8H2SO4 + 48NO2 + 16H2O}.$

Water. One mole of $\ce{S8}$ gives 16 mol of water, $16\times18=288$ g.

Answer: 288 (key: 288.00 to 288.30)

Topics:Balancing redox reactions Group 16

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JEE Advanced 2019 · Paper 2, Chemistry question 9