JEE Advanced 2019 · Paper 2 · Chemistry Q5

ChemistryMultiple correct+4 / -1Question 23 of 54

Which of the following reactions produce(s) propane as a major product?

Answer and worked solution

Official answer: A, C

(A) Soda-lime decarboxylation removes one carbon: $\ce{C3H7COONa -> C3H8}$ . Propane. ✓
(B) Kolbe electrolysis couples two propyl radicals, giving hexane. ✗
(C) Zn/HCl reduces 1-chloropropane to propane. ✓
(D) Zn removes the two vicinal bromines from 1,2-dibromopropane, giving propene. ✗

(A), (C)

Topics:Alkanes Polyhalogen compounds

JEE Advanced 2019 · Paper 2, Chemistry question 5