JEE Advanced 2019 · Paper 2 · Chemistry Q4

← JEE Advanced 2019 · Paper 2

ChemistryMultiple correct+4 / -1Question 22 of 54

The ground state energy of hydrogen atom is −13.6 eV. Consider an electronic state $\Psi$ of $\ce{He+}$ whose energy, azimuthal quantum number and magnetic quantum number are −3.4 eV, 2 and 0, respectively. Which of the following statement(s) is(are) true for the state $\Psi$ ?

It is a

4d

state

It has 2 angular nodes

It has 3 radial nodes

The nuclear charge experienced by the electron in this state is less than

2e

, where

e

is the magnitude of the electronic charge

Answer and worked solution

Official answer: A, B

Find n. For $\ce{He+}$ ,
$E_n=-13.6\frac{Z^2}{n^2}=-\frac{54.4}{n^2}=-3.4\implies n=4.$
With $l=2$ this is a $4d$ state.

The statements.

(A) It is a $4d$ state. True.
(B) It has $l=2$ angular nodes. True.
(C) It has $n-l-1=1$ radial node, not 3. False.
(D) With a single electron there is no shielding, so the electron feels the full $2e$ . False.

(A), (B)

Topics:Quantum numbers Bohr model Orbitals and their shapes

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JEE Advanced 2019 · Paper 2, Chemistry question 4