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← JEE Advanced 2017 · Paper 2
MathematicsSingle correct+3Question 52 of 54

JEE Advanced 2017 · Paper 2, Mathematics question 16

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PARAGRAPH 1

Let OO be the origin, and OX→\overrightarrow{OX}, OY→\overrightarrow{OY}, OZ→\overrightarrow{OZ} be three unit vectors in the directions of the sides QR→\overrightarrow{QR}, RP→\overrightarrow{RP}, PQ→\overrightarrow{PQ}, respectively, of a triangle PQRPQR.

If the triangle PQRPQR varies, then the minimum value of

cos⁡(P+Q)+cos⁡(Q+R)+cos⁡(R+P)\cos(P + Q) + \cos(Q + R) + \cos(R + P)

is

Choose one option
Answer and worked solution

Official answer: B

Rewrite. Since P+Q=π−RP+Q=\pi-R, and similarly for the others,
cos⁡(P+Q)+cos⁡(Q+R)+cos⁡(R+P)=−(cos⁡P+cos⁡Q+cos⁡R).\cos(P+Q)+\cos(Q+R)+\cos(R+P)=-(\cos P+\cos Q+\cos R).

Bound. In a triangle, cos⁡P+cos⁡Q+cos⁡R=1+4sin⁡P2sin⁡Q2sin⁡R2≤32\cos P+\cos Q+\cos R=1+4\sin\frac P2\sin\frac Q2\sin\frac R2\le\frac32, with equality for an equilateral triangle.

Minimum. −32-\dfrac32.

(B)