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← JEE Advanced 2017 · Paper 2
MathematicsSingle correct+3Question 51 of 54

JEE Advanced 2017 · Paper 2, Mathematics question 15

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PARAGRAPH 1

Let OO be the origin, and OX→\overrightarrow{OX}, OY→\overrightarrow{OY}, OZ→\overrightarrow{OZ} be three unit vectors in the directions of the sides QR→\overrightarrow{QR}, RP→\overrightarrow{RP}, PQ→\overrightarrow{PQ}, respectively, of a triangle PQRPQR.

∣OX→×OY→∣=|\overrightarrow{OX} \times \overrightarrow{OY}| =

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Answer and worked solution

Official answer: A

The angle between the directions QR→\overrightarrow{QR} and RP→\overrightarrow{RP} is π−R\pi-R. So
∣OX→×OY→∣=sin⁡(π−R)=sin⁡R=sin⁡(P+Q).|\overrightarrow{OX}\times\overrightarrow{OY}|=\sin(\pi-R)=\sin R=\sin(P+Q).

(A)