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← JEE Advanced 2017 · Paper 2
ChemistrySingle correct+3Question 34 of 54

JEE Advanced 2017 · Paper 2, Chemistry question 16

Passage

PARAGRAPH 1

Upon heating KClOX3\ce{KClO3} in the presence of catalytic amount of MnOX2\ce{MnO2}, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with pure HNOX3\ce{HNO3} gives Y and Z.

Y and Z are, respectively

Choose one option
Answer and worked solution

Official answer: B

PX4OX10\ce{P4O10} is a powerful dehydrating agent. It strips water from nitric acid:
PX4OX10+4 HNOX3→4 HPOX3+2 NX2OX5.\ce{P4O10 + 4HNO3 -> 4HPO3 + 2N2O5}.
So Y is NX2OX5\ce{N2O5} and Z is HPOX3\ce{HPO3}.

(B)