JEE Advanced 2017 · Paper 2 · Chemistry Q15

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ChemistrySingle correct+3Question 33 of 54

Passage

PARAGRAPH 1

Upon heating $\ce{KClO3}$ in the presence of catalytic amount of $\ce{MnO2}$ , a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with pure $\ce{HNO3}$ gives Y and Z.

W and X are, respectively

\ce{O3}

and

\ce{P4O6}

\ce{O2}

and

\ce{P4O6}

\ce{O2}

and

\ce{P4O10}

\ce{O3}

and

\ce{P4O10}

Answer and worked solution

Official answer: C

$\ce{2KClO3 ->[MnO2][\Delta] 2KCl + 3O2}$ , so W is $\ce{O2}$ .
With excess $\ce{O2}$ , white phosphorus burns to $\ce{P4O10}$ , so X is $\ce{P4O10}$ .

(C)

Topics:Group 15 Group 16

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JEE Advanced 2017 · Paper 2, Chemistry question 15