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← JEE Advanced 2016 · Paper 1
ChemistryInteger+3Question 35 of 54

JEE Advanced 2016 · Paper 1, Chemistry question 35

The number of geometric isomers possible for the complex [CoLX2ClX2]X−\ce{[CoL2Cl2]^-} (L=HX2NCHX2CHX2OX−)(\mathrm L=\ce{H2NCH2CH2O^-}) is

Answer and worked solution

Official answer: 5

[CoLX2ClX2]X−\ce{[CoL2Cl2]^-} is an octahedral M(AB)X2aX2\ce{M(AB)2a2} complex, with AB the unsymmetrical N,O-chelate.

Two Cl trans. The two chelates lie in the equatorial plane, with N trans to N or N trans to O: 2 isomers.

Two Cl cis. Each Cl is trans to a donor atom of a chelate:

  • N trans N (O's trans to the Cl's): 1 isomer;
  • O trans O (N's trans to the Cl's): 1 isomer;
  • N trans O: 1 isomer.
    That is 3 isomers.

Total: 5 geometric isomers.

Answer: 5