JEE Advanced 2015 · Paper 1, Chemistry question 36

In base, H₂O₂ is a reducing agent:
$$\ce{2Fe^{3+} + H2O2 + 2OH- -> 2Fe^{2+} + O2 + 2H2O}.$$
(A) is true. Na₂O₂ in water gives NaOH and H₂O₂, the same conditions, so (B) is true.

In acid, H₂O₂ oxidises Fe²⁺ to Fe³⁺ instead, so (C) and (D) are false.

(A), (B)