JEE Advanced 2015 · Paper 1 · Chemistry Q23

ChemistryInteger+4Question 23 of 60

The total number of lone pairs of electrons in $\ce{N2O3}$ is

Your answer

Answer and worked solution

Official answer: 8

Lewis structure. N₂O₃ is $\ce{O=N-NO2}$ , with $2(5)+3(6)=28$ valence electrons, i.e. 14 pairs.

Bond pairs. N=O (2), N-N (1), N=O (2) and N-O (1): 6 bonding pairs.

Lone pairs. $14-6=8$ .

Answer: 8

Topics:Covalent bonding and Lewis structures Group 15

JEE Advanced 2015 · Paper 1, Chemistry question 23