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← JEE Advanced 2014 · Paper 2
ChemistrySingle correct+3 / -1Question 30 of 60

JEE Advanced 2014 · Paper 2, Chemistry question 30

Assuming 2s-2p mixing is NOT operative, the paramagnetic species among the following is

Choose one option
Answer and worked solution

Official answer: C

Without 2s-2p mixing the order is σ2s<σ∗2s<σ2pz<π2px=π2py<π∗2p<σ∗2pz\sigma2s<\sigma^*2s<\sigma2p_z<\pi2p_x=\pi2p_y<\pi^*2p<\sigma^*2p_z.

Valence electrons:

  • BeX2\ce{Be2} (4): σ2s2σ∗2s2\sigma2s^2\sigma^*2s^2. Diamagnetic.
  • BX2\ce{B2} (6): …σ2pz2\ldots\sigma2p_z^2. Diamagnetic.
  • CX2\ce{C2} (8): …σ2pz2 π2px1π2py1\ldots\sigma2p_z^2\,\pi2p_x^1\pi2p_y^1. Two unpaired electrons: paramagnetic.
  • NX2\ce{N2} (10): …σ2pz2π2p4\ldots\sigma2p_z^2\pi2p^4. Diamagnetic.

(C)