JEE Advanced 2014 · Paper 2 · Chemistry Q25

ChemistrySingle correct+3 / -1Question 25 of 60

The product formed in the reaction of $\ce{SOCl2}$ with white phosphorous is

\ce{PCl3}

\ce{SO2Cl2}

\ce{SCl2}

\ce{POCl3}

Answer and worked solution

Official answer: A

Reaction. Thionyl chloride chlorinates white phosphorus:
$\ce{P4 + 8SOCl2 -> 4PCl3 + 4SO2 + 2S2Cl2}.$
The phosphorus product is $\ce{PCl3}$ .

(A)

Topics:Group 15

JEE Advanced 2014 · Paper 2, Chemistry question 25