JEE Advanced 2014 · Paper 2 · Chemistry Q24

ChemistrySingle correct+3 / -1Question 24 of 60

Hydrogen peroxide in its reaction with $\ce{KIO4}$ and $\ce{NH2OH}$ respectively, is acting as a

reducing agent, oxidising agent

reducing agent, reducing agent

oxidising agent, oxidising agent

oxidising agent, reducing agent

Answer and worked solution

Official answer: A

With $\ce{KIO4}$ : $\ce{KIO4 + H2O2 -> KIO3 + H2O + O2}$ . Periodate is reduced, and $\ce{H2O2}$ is oxidised to $\ce{O2}$ : a reducing agent.
With $\ce{NH2OH}$ : $\ce{H2O2}$ oxidises hydroxylamine (N at −1) to higher oxidation states (e.g. $\ce{NH2OH + 2H2O2 -> HNO2 + 3H2O}$ ), itself being reduced to water: an oxidising agent.

(A)

Topics:Water and hydrogen peroxide Oxidation number

JEE Advanced 2014 · Paper 2, Chemistry question 24