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← JEE Advanced 2013 · Paper 2
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JEE Advanced 2013 · Paper 2, Chemistry question 31

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Paragraph for Questions 31 and 32

The reactions of ClX2\ce{Cl2} gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The ClX2\ce{Cl2} gas reacts with SOX2\ce{SO2} gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, T.

P and Q, respectively, are the sodium salts of

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Answer and worked solution

Official answer: A

Cold dilute NaOH: ClX2+2 NaOH→NaCl+NaOCl+HX2O\ce{Cl2 + 2NaOH -> NaCl + NaOCl + H2O} (hypochlorite, P).

Hot concentrated NaOH: 3 ClX2+6 NaOH→5 NaCl+NaClOX3+3 HX2O\ce{3Cl2 + 6NaOH -> 5NaCl + NaClO3 + 3H2O} (chlorate, Q).

(A)

Topics:Group 17