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← JEE Advanced 2013 · Paper 1
PhysicsInteger+4 / -1Question 16 of 60

JEE Advanced 2013 · Paper 1, Physics question 16

The work functions of Silver and Sodium are 4.6 and 2.3 eV, respectively. The ratio of the slope of the stopping potential versus frequency plot for Silver to that of Sodium is

Answer and worked solution

Official answer: 1

Einstein's equation. eV0=hν−ϕeV_0=h\nu-\phi, so V0=heν−ϕeV_0=\dfrac he\nu-\dfrac\phi e. The slope he\dfrac he is the same for every metal: ratio 1.

Answer: 1