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← JEE Advanced 2013 · Paper 1
MathematicsInteger+4 / -1Question 56 of 60

JEE Advanced 2013 · Paper 1, Mathematics question 56

The coefficients of three consecutive terms of (1+x)n+5(1+x)^{n+5} are in the ratio 5 : 10 : 14. Then n=n=

Answer and worked solution

Official answer: 6

Ratios. With N=n+5N=n+5 and terms (Nr−1),(Nr),(Nr+1)\binom N{r-1},\binom Nr,\binom N{r+1}:
N−r+1r=2,N−rr+1=75.\frac{N-r+1}r=2,\qquad\frac{N-r}{r+1}=\frac75.

Solve. N=3r−1N=3r-1 and 5N=12r+75N=12r+7 give r=4r=4, N=11N=11, so n=6n=6.

Answer: 6