JEE Advanced 2013 · Paper 1 · Chemistry Q26

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ChemistrySingle correct+2Question 26 of 60

Upon treatment with ammoniacal $\ce{H2S}$ , the metal ion that precipitates as a sulfide is

Fe(III)

Al(III)

Mg(II)

Zn(II)

Answer and worked solution

Official answer: D

Group IV of qualitative analysis. Ammoniacal H₂S (high S²⁻ concentration) precipitates ZnS (white). Fe³⁺ and Al³⁺ are precipitated earlier as hydroxides by NH₄OH/NH₄Cl, and Mg²⁺ stays in solution.

(D)

Topics:Cation analysis

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JEE Advanced 2013 · Paper 1, Chemistry question 26