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ChemistrySingle correct+2Question 25 of 60

JEE Advanced 2013 · Paper 1, Chemistry question 25

The arrangement of XX−\ce{X-} ions around AX+\ce{A+} ion in solid AX is given in the figure (not drawn to scale). If the radius of XX−\ce{X-} is 250 pm, the radius of AX+\ce{A+} is

Six large X⁻ spheres packed around a small black A⁺ ion at their centre (an octahedral void); key: open circle X⁻, filled circle A⁺.
Choose one option
Answer and worked solution

Official answer: A

Octahedral void. Six X⁻ ions surround A⁺, so r+r−=0.414\dfrac{r_+}{r_-}=0.414 at contact.

Radius. r+=0.414×250≈104r_+=0.414\times250\approx104 pm.

(A)

Topics:Packing efficiency
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