IIT-JEE 2012 · Paper 2 · Physics Q7

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PhysicsSingle correct+3 / -1Question 7 of 60

A student is performing the experiment of Resonance Column. The diameter of the column tube is 4 cm. The frequency of the tuning fork is 512 Hz. The air temperature is 38 °C in which the speed of sound is 336 m/s. The zero of the meter scale coincides with the top end of the Resonance Column tube. When the first resonance occurs, the reading of the water level in the column is

14.0 cm

15.2 cm

16.4 cm

17.6 cm

Answer and worked solution

Official answer: B

Wavelength. $\lambda=\dfrac{336}{512}=0.656$ m, so $\dfrac\lambda4=16.4$ cm.

End correction. $e=0.3d=0.3\times4=1.2$ cm. The first resonance is at $L+e=\lambda/4$ :
$L=16.4-1.2=15.2\text{ cm}.$
The scale's zero is at the top of the tube, so this is the reading.

(B)

Topics:Speed of sound by resonance tube Organ pipes and resonance

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IIT-JEE 2012 · Paper 2, Physics question 7