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← IIT-JEE 2012 · Paper 2
PhysicsSingle correct+3 / -1Question 5 of 60

IIT-JEE 2012 · Paper 2, Physics question 5

Two moles of ideal helium gas are in a rubber balloon at 30 °C. The balloon is fully expandable and can be assumed to require no energy in its expansion. The temperature of the gas in the balloon is slowly changed to 35 °C. The amount of heat required in raising the temperature is nearly (take R=8.31R=8.31 J/mol.K)

Choose one option
Answer and worked solution

Official answer: D

Process. A freely expanding balloon keeps the gas at atmospheric pressure, so the heating is at constant pressure.

Heat. Helium is monatomic, Cp=52RC_p=\frac52R:
Q=nCpΔT=2×52×8.31×5≈208 J.Q=nC_p\Delta T=2\times\frac52\times8.31\times5\approx208\text{ J}.

(D)