IIT-JEE 2011 · Paper 2 · Physics Q37

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PhysicsInteger+4Question 37 of 60

A series R-C combination is connected to an AC voltage of angular frequency $\omega=500$ radian/s. If the impedance of the R-C circuit is $R\sqrt{1.25}$ , the time constant (in millisecond) of the circuit is

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Answer and worked solution

Official answer: 4

Reactance. $Z^2=R^2+X_C^2=1.25R^2$ , so $X_C=\frac R2$ .

Time constant. $\dfrac1{\omega C}=\dfrac R2$ , so $RC=\dfrac2\omega=\dfrac2{500}$ s $=4$ ms.

Answer: 4

Topics:Reactance and impedance RC circuits

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IIT-JEE 2011 · Paper 2, Physics question 37