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← IIT-JEE 2011 · Paper 2
PhysicsInteger+4Question 33 of 60

IIT-JEE 2011 · Paper 2, Physics question 33

A train is moving along a straight line with a constant acceleration 'aa'. A boy standing in the train throws a ball forward with a speed of 10 m/s, at an angle of 60° to the horizontal. The boy has to move forward by 1.15 m inside the train to catch the ball back at the initial height. The acceleration of the train, in m/s², is

Answer and worked solution

Official answer: 5

Train frame. The ball has ux=5u_x=5 m/s, uy=53u_y=5\sqrt3 m/s and a backward pseudo-acceleration aa.

Flight time T=2uyg=3T=\dfrac{2u_y}g=\sqrt3 s.

Displacement relative to the boy. 53−12a(3)=1.155\sqrt3-\frac12a(3)=1.15, so 8.66−1.5a=1.158.66-1.5a=1.15 and a≈5a\approx5 m/s².

Answer: 5