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← IIT-JEE 2011 · Paper 2
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IIT-JEE 2011 · Paper 2, Physics question 28

A wooden block performs SHM on a frictionless surface with frequency, ν0\nu_0. The block carries a charge +Q+Q on its surface. If now a uniform electric field E⃗\vec E is switched-on as shown, then the SHM of the block will be

Block carrying +Q on a horizontal frictionless floor, attached by a spring to a wall on the right; the field E points to the right.
Choose one option
Answer and worked solution

Official answer: A

New equilibrium. The constant force QEQE shifts the mean position by QEk\dfrac{QE}k (spring compressed).

Frequency. The restoring force about the new mean is still −kx-kx, so ν=12πkm=ν0\nu=\dfrac1{2\pi}\sqrt{\dfrac km}=\nu_0 is unchanged.

(A)