IIT-JEE 2011 · Paper 2 · Physics Q27

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PhysicsSingle correct+3 / -1Question 27 of 60

The density of a solid ball is to be determined in an experiment. The diameter of the ball is measured with a screw gauge, whose pitch is 0.5 mm and there are 50 divisions on the circular scale. The reading on the main scale is 2.5 mm and that on the circular scale is 20 divisions. If the measured mass of the ball has a relative error of 2%, the relative percentage error in the density is

0.9%

2.4%

3.1%

4.2%

Answer and worked solution

Official answer: C

Screw gauge. Least count $=\frac{0.5}{50}=0.01$ mm. Diameter $d=2.5+20\times0.01=2.70$ mm.

Error in density. $\rho=\dfrac{m}{\frac\pi6d^3}$ , so
$\frac{\Delta\rho}\rho=\frac{\Delta m}m+3\frac{\Delta d}d=2\%+3\times\frac{0.01}{2.70}\times100\%=2\%+1.1\%=3.1\%.$

(C)

Topics:Errors in measurement Vernier callipers and screw gauge

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IIT-JEE 2011 · Paper 2, Physics question 27