IIT-JEE 2010 · Paper 1 · Physics Q79

PhysicsInteger+3Question 79 of 84

When two progressive waves $y_1=4\sin(2x-6t)$ and $y_2=3\sin\left(2x-6t-\dfrac\pi2\right)$ are superimposed, the amplitude of the resultant wave is

Your answer

Answer and worked solution

Official answer: 5

Phase difference. The waves have the same $k$ and $\omega$ and differ in phase by $\frac\pi2$ .

Amplitude.
$A=\sqrt{4^2+3^2+2\cdot4\cdot3\cos\frac\pi2}=\sqrt{25}=5.$

Answer: 5

Topics:Superposition and interference

IIT-JEE 2010 · Paper 1, Physics question 79