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← IIT-JEE 2009 · Paper 2
MathematicsInteger+4 / -1Question 32 of 57

IIT-JEE 2009 · Paper 2, Mathematics question 32

Let (x,y,z)(x,y,z) be points with integer coordinates satisfying the system of homogeneous equations:
3x−y−z=0,−3x+z=0,−3x+2y+z=0.3x-y-z=0,\qquad-3x+z=0,\qquad-3x+2y+z=0.
Then the number of such points for which x2+y2+z2≤100x^2+y^2+z^2\le100 is

Answer and worked solution

Official answer: 7

Solve. The second equation gives z=3xz=3x; the first then gives y=0y=0; the third, −3x+3x=0-3x+3x=0, holds. The solutions are (x,0,3x)(x,0,3x).

Count. x2+9x2≤100x^2+9x^2\le100 means ∣x∣≤10|x|\le\sqrt{10}, so x∈{−3,…,3}x\in\{-3,\ldots,3\}: 7 points.

Answer: 7