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← IIT-JEE 2009 · Paper 1
ChemistryMultiple correct+4 / -1Question 12 of 60

IIT-JEE 2009 · Paper 1, Chemistry question 12

The correct statement(s) about the compound HX3C(HO)HC−CH=CH−CH(OH)CHX3\ce{H3C(HO)HC-CH=CH-CH(OH)CH3} (X) is(are)

Choose one or more options
Answer and worked solution

Official answer: A, D

Stereo elements. CHX3CH(OH)−CH=CH−CH(OH)CHX3\ce{CH3CH(OH)-CH=CH-CH(OH)CH3} (hex-3-ene-2,5-diol) has two identical stereocentres (C2, C5) and a C=C that can be cis or trans.

  • For each geometry, two identical stereocentres give three stereoisomers: an enantiomeric pair (R,R)/(S,S) and a meso form (R,S).
  • Total: 3+3=63+3=6 stereoisomers. (A) is true.
  • Enantiomers: for either geometry only the (R,R)/(S,S) pair, i.e. 2. So (C) is false and (D) is true.
  • (B) is false: the six stereoisomers fall into four sets that are diastereomeric to one another (trans chiral pair, trans meso, cis chiral pair, cis meso), not three.

(A), (D)