IIT-JEE 2009 · Paper 1 · Chemistry Q3

← IIT-JEE 2009 · Paper 1

ChemistrySingle correct+3 / -1Question 3 of 60

Among the electrolytes $\ce{Na2SO4}$ , $\ce{CaCl2}$ , $\ce{Al2(SO4)3}$ and $\ce{NH4Cl}$ , the most effective coagulating agent for $\ce{Sb2S3}$ sol is

\ce{Na2SO4}

\ce{CaCl2}

\ce{Al2(SO4)3}

\ce{NH4Cl}

Answer and worked solution

Official answer: C

Hardy-Schulze rule. $\ce{Sb2S3}$ is a negatively charged sol, so it is coagulated by cations, and the higher the cation's charge the stronger the effect. $\ce{Al^{3+}}$ has the highest charge.

(C) $\ce{Al2(SO4)3}$

Topics:Colloids

← Previous question Next question →

IIT-JEE 2009 · Paper 1, Chemistry question 3